global — Easy Playground

Declares a variable inside a function as belonging to the global scope

Python Playground

count = 0

def increment():
    global count
    count += 1

increment()
increment()
increment()
print(f"Count: {count}")

# Without global, assignment creates a local variable
x = "global"
def no_global():
    x = "local"  # creates a new local x
    print(f"Inside: {x}")

no_global()
print(f"Outside: {x}")

Output

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Without 'global', assigning to a variable inside a function creates a local variable. 'global' tells Python to use the module-level variable instead.

Challenge

Try modifying the code above to explore different behaviors. Can you extend the example to handle a new use case?

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