any() — Easy Playground

Returns True if at least one element in an iterable is truthy

Python Playground

print(any([False, False, True]))
print(any([0, 0, 0]))
print(any([]))

Output

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any() is a built-in function that returns true if at least one element in an iterable is truthy.

Try modifying the code above to explore different behaviors. Can you extend the example to handle a new use case?